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Re: find -execdir executes in wrong dir


Am 22.11.2010 12:19, schrieb Corinna Vinschen:
On Nov 21 05:02, pdanford wrote:
I just upgraded to version 1.7.7-1 and the following find command is
broken (which used to work correctly in a recent 1.7x version):

C:\cygwin\bin\find . -name file.txt -type f -execdir pwd ';'

Apparently, if there are say 10 matching file.txt files, -execdir
executes the command in the first dir over and over. However, the
following use of find works correctly:

C:\cygwin\bin\find . -name file.txt -type f -execdir pwd '{}' +
It appears that this is a problem in find 3.5.9.

I can reproduce this problem, even under Cygwin 1.7.5, and I examined
the strace output.  What happens is that find forks for each call to
pwd.  The forked find then calls fchdir before calling exec("pwd").

And here's the problem.  Each single fchdir is called with the exact
same directory descriptor.  There is an open file descriptor (fd 7)
which holds a handle to the *correct* directory, but the forked find
calls fchdir(4), which is a file descriptor holding the first directory
containing the file.

This does not occur when using find 3.5.8.

Eric? Would you mind to have a look?


Thanks, Corinna


The behaviour of find -execdir is documented in the info pages. From the info page:

 -- Action: -execdir command ;
     Execute COMMAND; true if zero status is returned.  `find' takes
     all arguments after `-execdir' to be part of the command until an
     argument consisting of `;' is reached.  It replaces the string
     `{}' by the current file name being processed everywhere it occurs
     in the command.  Both of these constructions need to be escaped
     (with a `\') or quoted to protect them from expansion by the
     shell.  The command is executed in the directory in which `find'
     was run.

So
    C:\cygwin\bin\find . -name file.txt -type f -execdir pwd ';'
execute the "pwd" in the current directory and do not change directories.

Regards
Dirk



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