Re: run batch w/o .bat?

[rich-paul at rich-paul dot net]

Actually, it looks like he was trying to do an oops script, for the
command after, which would be more like:

doh() {
	eval `history 2 | sed '2d;s/\s+[0-9]+\s+\([^\s]+\)/\1.bat'`
}
or for the non-sedders among us:
	gimme the last 2 lines of history
	(now the sed)
	throw away the last line (which will be doh)
	throw away the leading white, the group of digits, and the next
		white
	and append the .bat to the next token.

I haven't tested this, so sorry if the sed is wrong, but I have done an
eval of the output of history, w/o the first number, which worked.

On Tue, Jun 04, 2002 at 08:21:11PM -0700, Randall R Schulz wrote:
> Kevin,
> 
> BASH's aliases do not have all the functionality of CSH/TCSH aliases. In 
> particular, they cannot access the history mechanism. If you want to do 
> more than simple left-substitution of the command name, you should use a 
> shell procedure instead.
> 
> This should be equivalent to what you're trying:
> 
> bat() {
>          batName="$1.bat"
>          shift
>          "$batName" "$@"
> }
> 
> 
> Randall Schulz
> Mountain View, CA USA
> 
> 
> 
> At 14:46 2002-06-04, Barnhart, Kevin wrote:
> >Actually, I would settle for something like the following:
> >
> >alias 'bat'='!:0-0.bat !:1*'
> >
> >I'd like to add this into .bashrc.  Problem is that when I type in 'bat' at
> >the command line I get the following error:
> >bash: !:0-0.bat: command not found
> >
> >I'm tried to escape the bang with a '\', but to no avail.  If I type:
> >!:0-0.bat !:1*
> >at the command line then there is no problem--it does what is supposed to,
> >which is to append '.bat' to the 0-word of the previous command.
> >
> >Help?
> >
> >Kevin
> 
> 
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