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RE: Makefile that runs w.o. changes on Cygwin & Linux: how to do "rm -f $(TARGET)"?
- To: "'cygwin at cygwin dot com'" <cygwin at cygwin dot com>
- Subject: RE: Makefile that runs w.o. changes on Cygwin & Linux: how to do "rm -f $(TARGET)"?
- From: "Robinow, David" <drobinow at dayton dot adroit dot com>
- Date: Thu, 6 Sep 2001 17:39:10 -0400
MACH=`uname -s`
case "${MACH}" in
CYGWIN*)
EXE=".exe"
;;
*)
EXE=""
;;
esac
rm -f thing${EXE}
> -----Original Message-----
> From: Karr, David [mailto:david.karr@cacheflow.com]
> Sent: Thursday, September 06, 2001 4:38 PM
> To: 'cygwin@cygwin.com'
> Subject: Makefile that runs w.o. changes on Cygwin & Linux: how to do
> "rm -f $(TARGET)"?
>
>
> I have a little test application that I want to build and run
> without change
> on Cygwin and Linux. It almost works perfectly, except for
> the "clean"
> target. Is there any way to reference "thing" and have it
> mean "thing" on
> Linux, but "thing.exe" on Cygwin?
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